4x^2+6x-300=0

Solution for 4x^2+6x-300=0 equation:

4x^2+6x-300=0

a = 4; b = 6; c = -300;
Δ = b2-4ac
Δ = 62-4·4·(-300)
Δ = 4836
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4836}=\sqrt{4*1209}=\sqrt{4}*\sqrt{1209}=2\sqrt{1209}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-2\sqrt{1209}}{2*4}=\frac{-6-2\sqrt{1209}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+2\sqrt{1209}}{2*4}=\frac{-6+2\sqrt{1209}}{8}
$